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Find the LCM of
4(x²-y²) ,6(x³-y³) and 9(x³+y³)

Solution: Here, 1st Polynomial 4(x²-y²) = 2²(x+y) (x-y)
2nd

By Parker

Find the LCM of
4(x²-y²) ,6(x³-y³) and 9(x³+y³)

Solution: Here, 1st Polynomial 4(x²-y²) = 2²(x+y) (x-y)
2nd polynomial
6(x³-y³) = 2×3(x-y) (x²-xy+y²)
3rd Polynomial
9(x³+y³)= 3²(x+y) (x²-xy+y²)

Now, LCM of the polynomial
=2²x3²(x+y)(x-y) (x+y) (x²-xy+y²)
= 36(x²-y²) (x³+y³)
=36 (x²)³ – )(y²)³
=36(x⁶- y⁶)
hence proved​

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Parker

IF ABCD is a rhombus, find the measure of ZADC, given that ZBAC = 55
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1 thought on “Find the LCM of<br />4(x²-y²) ,6(x³-y³) and 9(x³+y³) <br /><br />Solution: Here, 1st Polynomial 4(x²-y²) = 2²(x+y) (x-y)<br />2nd”

  1. Step-by-step explanation:

    Solution: Here, 1st Polynomial 4(x²-y²) = 2²(x+y) (x-y)

    2nd polynomial

    2nd polynomial6(x³-y³) = 2×3(x-y) (x²-xy+y²)

    2nd polynomial6(x³-y³) = 2×3(x-y) (x²-xy+y²) 3rd Polynomial

    2nd polynomial6(x³-y³) = 2×3(x-y) (x²-xy+y²) 3rd Polynomial9(x³+y³)= 3²(x+y) (x²-xy+y²)

    Now, LCM of the polynomial

    Now, LCM of the polynomial=2²x3²(x+y)(x-y) (x+y) (x²-xy+y²)

    Now, LCM of the polynomial=2²x3²(x+y)(x-y) (x+y) (x²-xy+y²) = 36(x²-y²) (x³+y³)

    Now, LCM of the polynomial=2²x3²(x+y)(x-y) (x+y) (x²-xy+y²) = 36(x²-y²) (x³+y³)=36 (x²)³ – )(y²)³

    Now, LCM of the polynomial=2²x3²(x+y)(x-y) (x+y) (x²-xy+y²) = 36(x²-y²) (x³+y³)=36 (x²)³ – )(y²)³=36(x⁶- y⁶)

    Now, LCM of the polynomial=2²x3²(x+y)(x-y) (x+y) (x²-xy+y²) = 36(x²-y²) (x³+y³)=36 (x²)³ – )(y²)³=36(x⁶- y⁶)hence proved

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