Find the lateral surface area and the total surface area of a cuboid whose length = 16
cm, breadth = 12 cm and height = 8 cm​

Find the lateral surface area and the total surface area of a cuboid whose length = 16
cm, breadth = 12 cm and height = 8 cm​

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2 thoughts on “Find the lateral surface area and the total surface area of a cuboid whose length = 16<br />cm, breadth = 12 cm and height = 8 cm​”

  1. Answer:

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    Step-by-step explanation:

    Lateral Surface area = 2 height(length + breadth)

    = 2. (8) (16 + 12)

    = 16 × 28

    = 448 cm²

    Total Surface area = 2 (Length x Breadth + breadth x height + Length x height)

    = 2 [ (16).(12) + (12).(8) + (16).(8) ]

    = 2 [ 192 + 96 + 128 ]

    = 2 × 416

    = 832 cm²

    Lateral Surface Area of Cuboid = 448 cm²

    Total Surface Area of Cuboid = 832 cm²

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  2. [tex]\large\sf\underline{Given\::}[/tex]

    • Length of the cuboid = 16 cm.

    • Breadth of the cuboid = 12 cm.

    • Height of the cuboid = 8 cm.

    [tex]\large\sf\underline{To\:find\::}[/tex]

    • Total surface area ( TSA ) of the cuboid

    • Lateral surface area ( LSA ) of the cuboid

    [tex]\large\sf\underline{Solution\::}[/tex]

    We know ,

    [tex]\large{\mathfrak{TSA \:of\:the\:cuboid\:=\:2(lb+bh+lh)}}[/tex]

    where :

    • l stands for [tex]{\sf{{\pink{Length}}}}[/tex].

    • b stands for [tex]{\sf{{\pink{breadth}}}}[/tex].

    • h stands for [tex]{\sf{{\pink{height}}}}[/tex].

    Substituting the given values in the formula :

    [tex]\sf:\implies\:TSA\:=\:2[(16 \times 12) +(12 \times 8) +(16 \times 8) ][/tex]

    [tex]\sf:\implies\:TSA\:=\:2[192 + 96 + 128][/tex]

    [tex]\sf:\implies\:TSA\:=\:2[416][/tex]

    [tex]\sf:\implies\:TSA\:=\:2 \times 416[/tex]

    [tex]\small{\underline{\boxed{\mathrm\red{:\implies\:TSA\:=832\:sq.cm}}}}[/tex] ★

    ___________________________

    Now,

    [tex]\large{\mathfrak{LSA \:of\:the\:cuboid\:=\:2h(l+b)}}[/tex]

    where :

    • l stands for [tex]{\sf{{\pink{Length}}}}[/tex].

    • b stands for [tex]{\sf{{\pink{breadth}}}}[/tex].

    • h stands for [tex]{\sf{{\pink{height}}}}[/tex].

    Substituting the given values in the formula :

    [tex]\sf:\implies\:LSA\:=\:2 \times 8[16+12][/tex]

    [tex]\sf:\implies\:LSA\:=\:2 \times 8[28][/tex]

    [tex]\sf:\implies\:LSA\:=\:2 \times 8 \times 28[/tex]

    [tex]\sf:\implies\:LSA\:=\:16 \times 28[/tex]

    [tex]\small{\underline{\boxed{\mathrm\red{:\implies\:LSA\:=448\:sq.cm}}}}[/tex] ★

    ___________________________

    !! Hope it helps !!

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