Find the height of a parallelogram whose area is 542

and the base is

9.​

2 thoughts on “Find the height of a parallelogram whose area is 542<br /><br />and the base is <br /><br /> 9.​”

1. [tex] \huge\mathfrak \blue{Given}[/tex]

   Area of parallelogram = 542

   Base of parallelogram = 9

   [tex] \huge \mathfrak \blue{Find}[/tex]

   [tex] \sf \ \: Height \: of \: parallelogram [/tex]

   [tex]\huge\mathfrak\red{Solution}[/tex]

   [tex] \sf \: \: Area \: of \: parallelogram = base \: \times \: height \\ \\ \sf \: \frac{542}{9} \: = height\\ \\ \sf \: 542 = 9 \times height \\ \\ \sf \: 60.22 \: = height [/tex]

   Therefore the height of parallelogram is 60.22 approx.

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2. Answer:

   We know,

   Area of Parallelogram= Base × Height

   Or, Base × Height= Area of Parallelogram

   Or, Height= Area of Parallelogram/Base

   Or, Height= 542/9

   Or, Height= 60.222 (approx.)

   Answer: 60.222 (approx.)

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