Find the greatest number which divides the following completely :-(84,112,280) tell me all the proceedings About the author Madelyn
Answer: 28 Step-by-step explanation: The required greatest number = HCF {(280-84),(112-84),(280-112)} So, HCF (196,28,168) =28 Hence, the greatest number which divides 84,112,280 is 28. Plz rate this answer Reply
Step-by-step explanation: take out the HCF of 84,122,280 2 84. 2 122. 2. 280 2 56. 2 61. 2. 140 2 28. 61 1. 2. 70 2 14 2 35 7 7. 5. 7 1 7 1 84= 2*2*2*2*7 122=2*2*6 280= 2*2*2*2*5*7 H.C.F = 2*2 = 4 Reply
Answer:
28
Step-by-step explanation:
The required greatest number = HCF {(280-84),(112-84),(280-112)}
So, HCF (196,28,168) =28
Hence, the greatest number which divides 84,112,280 is 28.
Plz rate this answer
Step-by-step explanation:
take out the HCF of 84,122,280
2 84. 2 122. 2. 280
2 56. 2 61. 2. 140
2 28. 61 1. 2. 70
2 14 2 35
7 7. 5. 7
1 7 1
84= 2*2*2*2*7
122=2*2*6
280= 2*2*2*2*5*7
H.C.F = 2*2 = 4