find the greatest number that will divide 63,36 and 90 leaving remainder 9 in each case.​

2 thoughts on “find the greatest number that will divide 63,36 and 90 leaving remainder 9 in each case.​”

1. adding reminder 9 to all the numbers
   i) 63 + 9 = 72
   ii)36 + 9 = 45
   iii)90 + 9 = 99
   taking out prime factor s
   i) 72 = 2×2×2×3×3
   ii) 45 = 5×3×3
   iii) 99 = 11×3×3
   In this factors the HCF is 3×3 , i.e. 9
   : . the required no. is 9

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2. Answer:

   27

   Step-by-step explanation:

   63-9=54

   36-9=27

   90-9=81

   h. C. f. of 54,27,81

   27)54(2

   54

   ——

   0

   27)81(3

   81

   —

   0 so the h. C. f. of 54 ,27,81 is 27

   so the greatest number that divides 63,36,90 leaving reminder 9 in each case is 27

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