Find the following arithmetic progression.
1/15,1/12,1/10,——————-to 11tern in class 10 th​

2 thoughts on “Find the following arithmetic progression.<br />1/15,1/12,1/10,——————-to 11tern in class 10 th​”

1. Answer:

   First term(a)=1/15

   Common difference(d)=1/12-1/15=1/60

   Number of terms(n)=11

   Last term(tn)=?

   By using formula,we have

   tn=a+(n-1)d

   t11=1/15+(11-1)×1/60

   Or,t11=1/15+10/60

   .:t11=7/30

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2. Answer:

   11th term = 7/15

   Step-by-step explanation:

   first term, a = 1/15

   common difference = second term – first term

   d = (1/12) – (1/15) = 1/60

   theb 11th term = a+10d = (1/15) + (10/60) = 7/15

   hope this will help you

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