Find the first three terms of the sequence below.
Tn=n2−n+4

1 thought on “Find the first three terms of the sequence below.<br /> Tn=n2−n+4”

1. Answer:

   To find the ten terms of the sequence

   Tn=n^2–3n-4

   Plug in the values of n=1,2,3.. upto 10 to get the ten terms

   When n=1,T1=(1)^2–3*1–4=1–3–4=—6

   When n=2,T2=(2)^2–3*2–4=4–6–4=—6

   When n=3,T3=(3)^2–3*3–4=9–9–4=—4

   When n=4,T4=(4)^2–3*4–4=16–12–4=0

   When n=5,T5=(5)^2–3*5–4=25–15–4=6

   When n=6,T6=(6)^2–3*6–4=36–18–4=14

   When n=7,T7=7^2–3*7–4=49–21–4=24

   When n=8,T8=8^2–3*8–4=64–24–4=36

   When n=9,T9=9^2–3*9–4=81–27–4=50

   When n=10,T10=10^2–3*10–4=100–30–4=66

   The ten terms are,—6,—6,—4,0,6,14,25,36,50,66

   Step-by-step explanation:

   same Method

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