Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes​

2 thoughts on “Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes​”

1. Equation of a straight lines passing through (-8,4).

   making equal intercept on the co-ordinate axis.

   As we know that,

   Let we assume that x-intercept & y-intercept = t

   equation of line,

   ⇒ x/a + y/b = 1.

   We can write as,

   ⇒ x/t + y/t = 1.

   -8/t+4/t = 1.

   ⇒ 8 + 4 = t.

   ⇒ -4 = t.

   Put the value of t = -4 in equation, we get.

   ⇒ x/-4+ y/-4 = 1.

   ⇒ x + y = -4.

   ⇒ x+y+4= 0.

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2. [tex]\huge \bold\red{❥︎Answer❀✿°᭄}[/tex]

   Equation of a straight lines passing through (-8,4).

   making equal intercept on the co-ordinate axis.

   As we know that,

   Let we assume that x-intercept & y-intercept = t

   equation of line,

   ⇒ x/a + y/b = 1.

   We can write as,

   ⇒ x/t + y/t = 1.

   ⇒ -8/t + 4/t = 1.

   ⇒ -8 + 4 = t.

   ⇒ -4 = t.

   Put the value of t = -4 in equation, we get.

   ⇒ x/-4 + y/-4 = 1.

   ⇒ x + y = -4.

   ⇒ x + y + 4 = 0.

   MORE INFORMATION.

   Equation of straight lines parallel to axes.

   (1) = Equation of x-axis ⇒ y = 0.

   (2) = Equation of a line parallel to x-axes at a distance of b ⇒ y = b.

   (3) = Equation of y-axis ⇒ x = 0.

   (4) = Equation of a line parallel to y-axes and at a distance of a ⇒ x = a.

   Reply