find the distribution function of the total number of heads obtained in four tosses of a biased coin​

1 thought on “find the distribution function of the total number of heads obtained in four tosses of a biased coin​”

1. Step-by-step explanation:

   When a coin is tossed we have S={H,T}

   P (getting a head ) =12 and

   P (not getting a head) =(1−12)=12

   Let X be the random variable denoting the number of heads

   In 4 trials we may get 0 or 1 or 2 or 3 or 4 heads

   So. X may assume the values 0,1,2,3,4 .

   P(X=0)=.4C0.(12)0.(12)(4−0)=116

   P(X=1)=.4C1.(12)1.(12)(4−1)=14

   P(X=2)=.4C2.(12)2.(12)(4−2)=38

   P(X=3)=.4C3.(12)3.(12)(4−3)=14.

   P(X=4)=.4C4.(12)4.(12)(4−4)=116

   Hence the required probability distribution is given by

   (X:,0,1,2,3,4P(X):,116,14,38,14,116)

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