find the distribution function of the total number of heads obtained in four tosses of a biased coin​

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find the distribution function of the total number of heads obtained in four tosses of a biased coin​

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  1. Step-by-step explanation:

    When a coin is tossed we have S={H,T}

    P (getting a head ) =12 and

    P (not getting a head) =(1−12)=12

    Let X be the random variable denoting the number of heads

    In 4 trials we may get 0 or 1 or 2 or 3 or 4 heads

    So. X may assume the values 0,1,2,3,4 .

    P(X=0)=.4C0.(12)0.(12)(4−0)=116

    P(X=1)=.4C1.(12)1.(12)(4−1)=14

    P(X=2)=.4C2.(12)2.(12)(4−2)=38

    P(X=3)=.4C3.(12)3.(12)(4−3)=14.

    P(X=4)=.4C4.(12)4.(12)(4−4)=116

    Hence the required probability distribution is given by

    (X:,0,1,2,3,4P(X):,116,14,38,14,116)

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