Answer: let (x1,y1)=(2,8) and (x2,y2)=(6,8) by distance formula d(p,q)=root [(x2-x1)²,(y2-y1)²] = root[(6-2)²,(8-8)²] = root[(2)²] = root(4) d(p,q)= 2 units Reply
Answer: p(2,8 ) and q( 6,8) The answer is 4 Step-by-step explanation: we know distance between p and q is [tex] \sqrt{(6 – 2 {)}^{2} } + (8 – 8 {)}^{2} = 4[/tex] the anwer is 4 Reply
Answer:
let (x1,y1)=(2,8)
and (x2,y2)=(6,8)
by distance formula
d(p,q)=root [(x2-x1)²,(y2-y1)²]
= root[(6-2)²,(8-8)²]
= root[(2)²]
= root(4)
d(p,q)= 2 units
Answer:
p(2,8 ) and q( 6,8) The answer is 4
Step-by-step explanation:
we know
distance between p and q is
[tex] \sqrt{(6 – 2 {)}^{2} } + (8 – 8 {)}^{2} = 4[/tex]
the anwer is 4