1 thought on “Find the cost of painting the 4 walls of a room having length 12m<br />breadth 10m and height 8m at the rate of 35 per m²<br />”

Answer:

Step-by-step explanation:

Given Length of the room = 6m

Given Breadth of the room = 4m

Given Height of the room = 2.5m

As the room is in a cuboidal shape therefore to find the cost of painting the walls at ₹25 per sq. m, We first need to find out the Area of four walls of the room

Lateral Surface area of Cuboid = Area of four walls of the room

Therefore, Lateral surface area or Area of four walls = 2(l + b)h

where, l is the length, b is the breadth and h is the height of the room

Answer:Step-by-step explanation:Given Length of the room = 6m

Given Breadth of the room = 4m

Given Height of the room = 2.5m

As the room is in a cuboidal shape therefore to find the cost of painting the walls at ₹25 per sq. m, We first need to find out the Area of four walls of the room

Lateral Surface area of Cuboid = Area of four walls of the room

Therefore, Lateral surface area or Area of four walls = 2(l + b)h

where, l is the length, b is the breadth and h is the height of the room

put the given values of l,b and h in the formula.

=> 2(6 + 4)2.5

=> 2 × 10 × 2.5

=> 20 × 2.5

=> 50 sq. m

Now, Cost of painting 1 sq. m = ₹25

Cost of painting 50 sq. m = 25 × 50 = ₹ 1250