1 thought on “Find the cost of painting the 4 walls of a room having length 12m<br />breadth 10m and height 8m at the rate of 35 per m²<br />”
Answer:
Step-by-step explanation:
Given Length of the room = 6m
Given Breadth of the room = 4m
Given Height of the room = 2.5m
As the room is in a cuboidal shape therefore to find the cost of painting the walls at ₹25 per sq. m, We first need to find out the Area of four walls of the room
Lateral Surface area of Cuboid = Area of four walls of the room
Therefore, Lateral surface area or Area of four walls = 2(l + b)h
where, l is the length, b is the breadth and h is the height of the room
Answer:
Step-by-step explanation:
Given Length of the room = 6m
Given Breadth of the room = 4m
Given Height of the room = 2.5m
As the room is in a cuboidal shape therefore to find the cost of painting the walls at ₹25 per sq. m, We first need to find out the Area of four walls of the room
Lateral Surface area of Cuboid = Area of four walls of the room
Therefore, Lateral surface area or Area of four walls = 2(l + b)h
where, l is the length, b is the breadth and h is the height of the room
put the given values of l,b and h in the formula.
=> 2(6 + 4)2.5
=> 2 × 10 × 2.5
=> 20 × 2.5
=> 50 sq. m
Now, Cost of painting 1 sq. m = ₹25
Cost of painting 50 sq. m = 25 × 50 = ₹ 1250