Find the compound interest if ₹ 40,000 are invested for 2 years at the rate of 8 p.c.p.a.pls tell About the author Isabella
Answer: As per given question, Amount for the first year: A=P(1+ 100 R ) n =40000(1+8/100) 1 =40000×108/100=Rs. 43200 Now, amount for the second year: A=P(1+ 100 R ) n =43200(1+8/100) 1 =43200×108/100=Rs. 46656 Compound interest =Amount−Principle Rs. 46656−Rs. 43200=Rs. 3456 Reply
Answer: A=P(1+r/100)^t =40000(1+8/100)² =40000(108/100×108/100) =4×108×108 =46656 C.I=A-P =46656-40000 =6655,is your answer Reply
Answer:
As per given question,
Amount for the first year:
A=P(1+
100
R
)
n
=40000(1+8/100)
1
=40000×108/100=Rs. 43200
Now, amount for the second year:
A=P(1+
100
R
)
n
=43200(1+8/100)
1
=43200×108/100=Rs. 46656
Compound interest =Amount−Principle
Rs. 46656−Rs. 43200=Rs. 3456
Answer:
A=P(1+r/100)^t
=40000(1+8/100)²
=40000(108/100×108/100)
=4×108×108
=46656
C.I=A-P
=46656-40000
=6655,is your answer