1 thought on “find the area of the ∆ PQR whose vertices are P (5,2) ,Q (-3,7) and R (2,-4) ”
Solution!!
The concept of co-ordinate geometry has to be used here. The vertices of a triangle are given in the question. We are asked to find the area of the triangle.
P(5,2)
Q(–3,7)
R(2,–4)
Now, let’s use a suitable formula to find the area of the triangle.
Solution!!
The concept of co-ordinate geometry has to be used here. The vertices of a triangle are given in the question. We are asked to find the area of the triangle.
P(5 , 2)
Q(–3 , 7)
R(2 , –4)
Now, let’s use a suitable formula to find the area of the triangle.
Area = 1/2[x₁(y₂ – y₃) + x₂(y₃ – y₁) + x₃(y₁ – y₂)]
Here,
x₁ = 5
x₂ = -3
x₃ = 2
y₁ = 2
y₂ = 7
y₃ = -4
Area = 1/2[5(7 – (-4)) + (-3)(-4 – 2) + 2(2 – 7)]
Area = 1/2[5(7 + 4) + (-3)(-6) + 2(-5)]
Area = 1/2[5(11) + 18 – 10]
Area = 1/2[55 + 18 – 10]
Area = 1/2[63]
Area = 31.5 sq units