[tex]\large\underline{\sf{Solution-}}[/tex] Given that, [tex]\begin{gathered}\rm :\longmapsto\:2x + y=\left[\begin{array}{ccc}4&4&7\\7&3&4\end{array}\right]\end{gathered} – – – (1)[/tex] and [tex]\begin{gathered}\rm :\longmapsto\:x – 2y=\left[\begin{array}{ccc} – 3&2&1\\1& – 1&2\end{array}\right]\end{gathered} – – – (2)[/tex] On multiply equation (1) by 2, we get [tex]\begin{gathered}\rm :\longmapsto\:4x + 2y=\left[\begin{array}{ccc}8&8&14\\14&6&8\end{array}\right]\end{gathered} – – – (3)[/tex] On adding equation (3) and equation (2), we get [tex]\begin{gathered}\rm :\longmapsto\:5x =\left[\begin{array}{ccc}5&10&15\\15&5&10\end{array}\right]\end{gathered}[/tex] [tex]\begin{gathered}\bf :\longmapsto\:x =\left[\begin{array}{ccc}1&2&3\\3&1&2\end{array}\right]\end{gathered} – – – (4)[/tex] Now, Multiply equation (2) by 2, we get [tex]\begin{gathered}\rm :\longmapsto\:2x – 4y=\left[\begin{array}{ccc} – 6&4&2\\2& -2&4\end{array}\right]\end{gathered} – – – (5)[/tex] On Subtracting equation (2) from equation (1), we get [tex]\begin{gathered}\rm :\longmapsto\:5y=\left[\begin{array}{ccc} 10&0&5\\5& 5&0\end{array}\right]\end{gathered} – – – (5)[/tex] [tex]\begin{gathered}\bf :\longmapsto\:y=\left[\begin{array}{ccc} 2&0&1\\1& 1&0\end{array}\right]\end{gathered} – – – (6)[/tex] Reply
[tex]\large\underline{\sf{Solution-}}[/tex]
Given that,
[tex]\begin{gathered}\rm :\longmapsto\:2x + y=\left[\begin{array}{ccc}4&4&7\\7&3&4\end{array}\right]\end{gathered} – – – (1)[/tex]
and
[tex]\begin{gathered}\rm :\longmapsto\:x – 2y=\left[\begin{array}{ccc} – 3&2&1\\1& – 1&2\end{array}\right]\end{gathered} – – – (2)[/tex]
On multiply equation (1) by 2, we get
[tex]\begin{gathered}\rm :\longmapsto\:4x + 2y=\left[\begin{array}{ccc}8&8&14\\14&6&8\end{array}\right]\end{gathered} – – – (3)[/tex]
On adding equation (3) and equation (2), we get
[tex]\begin{gathered}\rm :\longmapsto\:5x =\left[\begin{array}{ccc}5&10&15\\15&5&10\end{array}\right]\end{gathered}[/tex]
[tex]\begin{gathered}\bf :\longmapsto\:x =\left[\begin{array}{ccc}1&2&3\\3&1&2\end{array}\right]\end{gathered} – – – (4)[/tex]
Now,
Multiply equation (2) by 2, we get
[tex]\begin{gathered}\rm :\longmapsto\:2x – 4y=\left[\begin{array}{ccc} – 6&4&2\\2& -2&4\end{array}\right]\end{gathered} – – – (5)[/tex]
On Subtracting equation (2) from equation (1), we get
[tex]\begin{gathered}\rm :\longmapsto\:5y=\left[\begin{array}{ccc} 10&0&5\\5& 5&0\end{array}\right]\end{gathered} – – – (5)[/tex]
[tex]\begin{gathered}\bf :\longmapsto\:y=\left[\begin{array}{ccc} 2&0&1\\1& 1&0\end{array}\right]\end{gathered} – – – (6)[/tex]