find M and N so that the following number is divisible by both 3 and 5. a) M56N, b) 45M7N, c) N608M About the author Mackenzie

Step-by-step explanation: (i) 1332 The given number = 1332 For a number to be divisible by 9 sum of digits must be divisible by 9. Sum of its digits = 1 + 3 + 3 + 2 = 9 Since 9 is divisible by 9, therefore 1332 is divisible by 9. (ii) 53247 The given number = 53247 For a number to be divisible by 9 sum of digits must be divisible by 9. Sum of its digits = 5 + 3 + 2 + 4 + 7 = 21 Since 21 is not divisible by 9, therefore 53247 is not divisible by 9. (iii) 4968 The given number = 4968 For a number to be divisible by 9 sum of digits must be divisible by 9. Sum of digits = 4 + 9 + 6 + 8 = 27 Since 27 is divisible by 9, therefore 4968 is divisible by 9. (iv) 200314 The given number = 200314 For a number to be divisible by 9 sum of digits must be divisible by 9. Sum of its digits = 2 + 0 + 0 + 3 + 1 + 4 = 10 Since 10 is not divisible by 9, therefore 200314 is not divisible by 9. Reply

Step-by-step explanation:(i) 1332

The given number = 1332

For a number to be divisible by 9 sum of digits must be divisible by 9.

Sum of its digits = 1 + 3 + 3 + 2 = 9

Since 9 is divisible by 9, therefore 1332 is divisible by 9.

(ii) 53247

The given number = 53247

For a number to be divisible by 9 sum of digits must be divisible by 9.

Sum of its digits = 5 + 3 + 2 + 4 + 7 = 21

Since 21 is not divisible by 9, therefore 53247 is not divisible by 9.

(iii) 4968

The given number = 4968

For a number to be divisible by 9 sum of digits must be divisible by 9.

Sum of digits = 4 + 9 + 6 + 8 = 27

Since 27 is divisible by 9, therefore 4968 is divisible by 9.

(iv) 200314

The given number = 200314

For a number to be divisible by 9 sum of digits must be divisible by 9.

Sum of its digits = 2 + 0 + 0 + 3 + 1 + 4 = 10

Since 10 is not divisible by 9, therefore 200314 is not divisible by 9.