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Father’s age is 3 times the age of his two children. After 5 years his age will be twice the sum of ages of two children. Find the

By Aubrey

Father’s age is 3 times the age of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

(Ans = Father’s age is 25 years)
Provide explanation how we get that.​

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Aubrey

Let PE S” and i € (n). Then we have lcp-leps,+1(P) 2 lcps;(P). Describe the case when equality holds.
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2 thoughts on “Father’s age is 3 times the age of his two children. After 5 years his age will be twice the sum of ages of two children. Find the”

  1. Answer:

    Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son. Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5. Thus the age of the father is 45.

    Hope it’s helpful for you

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  2. Answer:

    Father’s age =45 years

    Step-by-step explanation:

    Let the age of the sons be x and y.

    Given that Father’s age is three times the age of his two sons.

    Therefore, present age of father is 3(x+y)

    Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.

    Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

    3(x+y)+5 = 2(x+5+y+5)

    3x+3y+5 = 2x+10+2y+10

    3x+3y+5 = 2x+2y+20

    3x-2x+3y-2y = 20–5

    x+y = 15

    Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)

    Thus the age of the father is 45.

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