factorise the expression x y z(z square + 6 z- 16) divided 2 Y (Z – 2)​

2 thoughts on “factorise the expression x y z(z square + 6 z- 16) divided 2 Y (Z – 2)​”

1. Answer:

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   Step-by-step explanation:

   = xyz ( z^2 + 6z – 16 )

   2y ( z – 2 )

   = ( z^2 + 8z – 2z – 16 )

   2y ( z – 2 )

   = xyz [ z ( z + 8 ) – 2 ( z + 8 ) ]

   2y ( z – 2 )

   = xyz ( z – 2 ) ( z + 8 )

   2y ( z – 2 )

   = xyz ( z + 8 )

   2y

   = x × y × z ( z + 8 )

   2 × y

   = xy ( z + 8 )

   2

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2. 4yz(z

   2

   +6z−16)÷2y(z+8)

   2y(z+8)

   4yz(z

   2

   +8z−2z−16)

   z+8

   2z(z(z+8)−2(z+8))

   ⇒

   (z+8)

   2z[(z+8)(z−2)]

   2z(z−2)=2z

   2

   −4z.

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