SoluTion:– [tex]→\;{\sf{x²+2x-35 = 0}}[/tex] [tex]→\;{\sf{x²+7x-5x-35 = 0}}[/tex] [tex]→\;{\sf{x(x+7)-5(x+7) = 0}}[/tex] [tex]→\;{\sf{(x-5)(x+7) = 0}}[/tex] [tex]→\;{\red{\bold{x = 5\;(or)\;-7}}}[/tex] [tex]\Large{✓}[/tex] Hope It Helps You ✌️ Reply
Answer: Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers… Step-by-step explanation: [tex] {x}^{2} + 2x – 35 \\ {x}^{2} + 7x – 5x – 35 \\ {x}(x + 7) – 5(x + 7) \\ \pink{(x – 5)(x + 7)}[/tex] Reply
SoluTion:–
[tex]→\;{\sf{x²+2x-35 = 0}}[/tex]
[tex]→\;{\sf{x²+7x-5x-35 = 0}}[/tex]
[tex]→\;{\sf{x(x+7)-5(x+7) = 0}}[/tex]
[tex]→\;{\sf{(x-5)(x+7) = 0}}[/tex]
[tex]→\;{\red{\bold{x = 5\;(or)\;-7}}}[/tex]
[tex]\Large{✓}[/tex]
Hope It Helps You ✌️
Answer:
Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers…
Step-by-step explanation:
[tex] {x}^{2} + 2x – 35 \\ {x}^{2} + 7x – 5x – 35 \\ {x}(x + 7) – 5(x + 7) \\ \pink{(x – 5)(x + 7)}[/tex]