Answer: 101×99=(100+1)(100−1) We know suitable identity is (x+y)(x−y)=x 2 −y 2 Therefore, the value of (100+1)(100−1) is =(100) 2 −(1) 2 =10000−1 =9999 Reply
Answer: (square of 10 ) × 98 = 9800 (105 ) ² = 1125 (100 + 5 )²= 100² + 2×100×5 + 5² Step-by-step explanation: hope it helps Reply
Answer:
101×99=(100+1)(100−1)
We know suitable identity is (x+y)(x−y)=x
2
−y
2
Therefore, the value of (100+1)(100−1) is
=(100)
2
−(1)
2
=10000−1
=9999
Answer:
(square of 10 ) × 98 = 9800
(105 ) ² = 1125
(100 + 5 )²= 100² + 2×100×5 + 5²
Step-by-step explanation:
hope it helps