ers
the value of m for which the equation
(m + 4)x2 + (m + 1)x + 1 = 0 has real and
equal roots.​

1 thought on “ers<br />the value of m for which the equation<br />(m + 4)x2 + (m + 1)x + 1 = 0 has real and<br />equal roots.​”

1. Answer:

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   Step-by-step explanation:

   Given that the roots of the quadratic equation (4+m)x

   2

   +(m+1)x+1=0 are equal.

   ∴ the discriminant b

   2

   −4ac will be equal to 0.

   Here a=4+m,b=m+1,c=1

   ∴b

   2

   −4ac=(m+1)

   2

   −4(4+m)(1)=0

   ⇒(m+1)

   2

   −4(4+m)=0

   ⇒m

   2

   +2m+1−16−4m=0

   ⇒m

   2

   −2m−15=0

   ⇒(m−5)(m+3)=0

   ⇒m=5or−3

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