Express cos 68° + tan 76° in terms of angles between 0 & 45​

2 thoughts on “Express cos 68° + tan 76° in terms of angles between 0 & 45​”

1. Step-by-step explanation:

   Given:–

   cos 68° + tan 76°

   To find:–

   Express cos 68° + tan 76° in terms of angles between 0° & 45°

   Solution:–

   Given that : cos 68° + tan 76°

   It can be written as

   Cos (90°-22°) + Tan (90°- 14°)

   We know that

   Cos (90°-A) = Sin A

   Tan (90°-A) = Cot A

   So ,

   Cos (90°-22°)= Sin 22°

   Tan (90°-14°) = Cot 14°

   Cos (90°-22°) + Tan (90°- 14°)

   =>Sin 22° + Tan 14°

   Answer:–

   Cos 68°+ Tan 76° = Sin 22° + Cot 14°

   Used formulae:–

   • Cos (90°-A) = Sin A
   • Tan (90°-A) = Cot A

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2. Step-by-step explanation:

   cos 68° + tan 76° = cos (90° – 22°) + tan(90° – 22°) + tan (90° – 14°)

   = sin 22° + cot 14°

   [cos (90° – θ) = sin θ and tan (90° – θ) = cot θ]

   I think u have the answer.

   Anyway hope it will help u.

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