Example 28. Find cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 5, -7, -14 respectively. About the author Ximena
[tex]\huge\purple{\mid{\fbox{\underline{Answer:}}}\mid}\\\\[/tex] Given:– sum of the product of its zeroes taken two at a time the product of its zeroes as 5, -7, -14 respectively Find:– Find cubic polynomial with the sum of the product of its zeroes. Answer:– Let the zeroes be α, β and γ. Then, we have α + β + γ = 5 αβ + βγ + γα = -7 αβγ = -14 Now, required cubic polynomial => x³ – (α + β + γ)x² + (αβ + βγ + γα)x – αβγ => x³ – 5x² + (-7)x – (-14) => x³ – 5x – 7x + 14 So, x³ – 5x – 7x + 14 is the required cubic polynomial which satisfy the given conditions. [tex]\\\\\\[/tex] HOPE IT HELPS PLEASE MARK ME BRAINLIEST ☺️ Reply
[tex]\huge\purple{\mid{\fbox{\underline{Answer:}}}\mid}\\\\[/tex]
Given:–
Find:–
Answer:–
Let the zeroes be α, β and γ.
Then, we have
α + β + γ = 5
αβ + βγ + γα = -7
αβγ = -14
Now, required cubic polynomial
=> x³ – (α + β + γ)x² + (αβ + βγ + γα)x – αβγ
=> x³ – 5x² + (-7)x – (-14)
=> x³ – 5x – 7x + 14
So, x³ – 5x – 7x + 14 is the required cubic polynomial which satisfy the given conditions.
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