divide 184 into two parts such that one third of one part may exceed one-seventh of other part by 8​

1 thought on “divide 184 into two parts such that one third of one part may exceed one-seventh of other part by 8​”

1. Answer:

   1st part = 72

   2nd part = 112

   Step-by-step explanation:

   let us take, ‘x’ be the 1st part

   => the 2nd part = 184-x

   it is given that,

   (1/3)x = (1/7)(184-x) + 8

   => (1/3)x = (1/7)(184) – (1/7)(x) + 8

   => (1/3)x + (1/7)(x) = (184/7) + 8

   => (7+3)/(7*3) * x = (184+56)/7

   => 10x/21 = 240/7

   => 10x = (240/7) * 21

   => 10x = 240*3

   => x = (240*3)/10

   = 24*3

   = 72

   so, the 1st part = 72

   and the 2nd part = 184-72 = 112

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