Difference of two whole numbers is 33 and its ratio is 2:5 then find thosenumbers. About the author Athena
Step-by-step explanation: let the numbers be x and y Given : x – y = 33 (eqn no. 1) y/x = 2/5 (eqn no. 2) x – y = 33 x = 33 + y (substituting the value of x in eqn. no. 2) y/x = 2/5 y/(33+y) = 2/5 (cross multiplication) 5y = 2(33+y) 5y = 66 + 2y 5y – 2y = 66 3y = 66 y = 66/3 y = 22 (putting the value of y in eqn no. 1) x – y = 33 x – 22 = 33 x = 33 + 22 x = 55 hence the numbers are 22 and 55 Reply
Step by step explanation: Let’s assume: Let the first number be 2x. Let the second number be 5x. According to the question [tex] \: \: \sf \implies \: 5x – 2x = 33 \\ \\ \: \: \sf \implies \: 3x = 33 \\ \\ \: \: \: \: \sf \implies \: \dagger\therefore x = 11[/tex] Hence, the value of x is 11. Therefore,now put the value to find the numbers First number = 5x = 5 × 11 = 55 Second number = 2x = 2 × 11 = 22 Reply
Step-by-step explanation:
let the numbers be x and y
Given :
x – y = 33 (eqn no. 1)
y/x = 2/5 (eqn no. 2)
x – y = 33
x = 33 + y
(substituting the value of x in eqn. no. 2)
y/x = 2/5
y/(33+y) = 2/5
(cross multiplication)
5y = 2(33+y)
5y = 66 + 2y
5y – 2y = 66
3y = 66
y = 66/3
y = 22
(putting the value of y in eqn no. 1)
x – y = 33
x – 22 = 33
x = 33 + 22
x = 55
hence the numbers are 22 and 55
Step by step explanation:
Let’s assume:
According to the question
[tex] \: \: \sf \implies \: 5x – 2x = 33 \\ \\ \: \: \sf \implies \: 3x = 33 \\ \\ \: \: \: \: \sf \implies \: \dagger\therefore x = 11[/tex]
Hence, the value of x is 11.
Therefore,now put the value to find the numbers