Determine the value of k so that the following equation have no solution. 2x+3y=7, 6x- my=24 About the author Anna
Step-by-step explanation: Consider the given equations. 2x+3y=7 (k−1)x+(k+2)y=3k The general equations a 1 x+b 1 y=c 1 a 2 x+b 2 y=c 2 So, a 1 =2,b 1 =3,c 1 =7 a 2 =k−1,b 2 =k+2,c 2 =3k We know that the condition of infinite solution a 2 a 1 = b 2 b 1 = c 2 c 1 Therefore, k−1 2 = k+2 3 = 3k 7 ⇒ k−1 2 = k+2 3 ⇒2k+4=3k−3 ⇒k=7 Hence, the value of k is 7. Reply
Step-by-step explanation:
Consider the given equations.
2x+3y=7
(k−1)x+(k+2)y=3k
The general equations
a
1
x+b
1
y=c
1
a
2
x+b
2
y=c
2
So,
a
1
=2,b
1
=3,c
1
=7
a
2
=k−1,b
2
=k+2,c
2
=3k
We know that the condition of infinite solution
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Therefore,
k−1
2
=
k+2
3
=
3k
7
⇒
k−1
2
=
k+2
3
⇒2k+4=3k−3
⇒k=7
Hence, the value of k is 7.