Determine the nature of the roots of the quadratic equation 2x² – 3X -4 = 0 from their
discriminant (∆).​

2 thoughts on “Determine the nature of the roots of the quadratic equation 2x² – 3X -4 = 0 from their<br />discriminant (∆).​”

1. Answer:

   [tex]d = {b}^{2} – 4ac \\ = ( { – 3}^{2}) – 4 \times 2 \times – 4 \\ = 9 + 32 \\ = 41 \\ d < 41 \\ hence \: the \: two\: distinct \: and \: real \: root\\ [/tex]

   Reply

2. 2x²-3x-4=0

   compare equation with ax²+bx+c=0

   a=2, b=-3, c=-4

   b²-4ac= (-3)²-4×2×(-4)

   =9+32

   =41

   b²-4ac is greater than 0

   therefore, the roots of quadratic equation is real and equal.

   Reply