Decide whether the given sequence 24,17,10,3…is an A.P.? If yes find its common term (tn) . About the author Parker
Step-by-step explanation: Which of the following sequences are A.P. ? If they are A.P. find the common difference . (1) 2, 4, 6, 8,…. (2) 2, 52, 3, 73 ,…. (3) –10, –6, –2, 2… (4) 0.3, 0.33, 0.333,… (5) 0, –4, –8, –12,… (6) −15,−15,−15,… (7) 3, 3+2–√, 3+22–√, 3+32–√ (8) 127, 132, 137,… ANSWER: (1) 2, 4, 6, 8,…. The given sequence is an A.P. Common difference = Second term − First term = 4 − 2 = 2 (2) 2, 52, 3, 73 ,…. The given sequence is not an A.P. (3) –10, –6, –2, 2… The given sequence is an A.P. Common difference = Second term − First term = (−6) − (−10) = 4 (4) 0.3, 0.33, 0.333,… The given sequence is not an A.P. (5) 0, –4, –8, –12,… The given sequence is an A.P. Common difference = Second term − First term = (−4) − (0) = −4 (6) −15,−15,−15,… The given sequence is an A.P. Common difference = Second term − First term = (−15) − (−15) = 0 (7) 3, 3+2–√, 3+22–√, 3+32–√ The given sequence is an A.P. Common difference = Second term − First term = 3+2–√−3 = 2–√ (8) 127, 132, 137,… The given sequence is an A.P. Common difference = Second term − First term = (132) − (127) = 5 Reply
Step-by-step explanation:
Which of the following sequences are A.P. ? If they are A.P. find the common difference .
(1) 2, 4, 6, 8,….
(2) 2, 52, 3, 73 ,….
(3) –10, –6, –2, 2…
(4) 0.3, 0.33, 0.333,…
(5) 0, –4, –8, –12,…
(6) −15,−15,−15,…
(7) 3, 3+2–√, 3+22–√, 3+32–√
(8) 127, 132, 137,…
ANSWER:
(1) 2, 4, 6, 8,….
The given sequence is an A.P.
Common difference = Second term − First term
= 4 − 2
= 2
(2) 2, 52, 3, 73 ,….
The given sequence is not an A.P.
(3) –10, –6, –2, 2…
The given sequence is an A.P.
Common difference = Second term − First term
= (−6) − (−10)
= 4
(4) 0.3, 0.33, 0.333,…
The given sequence is not an A.P.
(5) 0, –4, –8, –12,…
The given sequence is an A.P.
Common difference = Second term − First term
= (−4) − (0)
= −4
(6) −15,−15,−15,…
The given sequence is an A.P.
Common difference = Second term − First term
= (−15) − (−15)
= 0
(7) 3, 3+2–√, 3+22–√, 3+32–√
The given sequence is an A.P.
Common difference = Second term − First term
= 3+2–√−3
= 2–√
(8) 127, 132, 137,…
The given sequence is an A.P.
Common difference = Second term − First term
= (132) − (127)
= 5