Answer: [tex] \huge \tt a)\color{red}10°C [/tex] [tex] \huge \tt b) \color{red}297°C[/tex] Explanation: a) Temperature in kelvin = Temperature in Celsius + 273 T(K) = 273 +T(°C) Using same formula, 283 = 273 + T(“C) T(°C) = 283-273 T(°C) = 10°C [tex] \tt =>\color{red}10°C [/tex] b) Using above formula, T(K) = 273 +T(C) T(°C) = T(k)-273 T(°C) = 570-273 T(°C) = 297°C [tex] \tt =>\color{red}297°C [/tex] Reply
283-273=10c
570-273=297c
hope it helps
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Answer:
[tex] \huge \tt a)\color{red}10°C [/tex]
[tex] \huge \tt b) \color{red}297°C[/tex]
Explanation:
a) Temperature in kelvin = Temperature in Celsius + 273
T(K) = 273 +T(°C)
Using same formula,
283 = 273 + T(“C)
T(°C) = 283-273
T(°C) = 10°C
[tex] \tt =>\color{red}10°C [/tex]
b) Using above formula,
T(K) = 273 +T(C)
T(°C) = T(k)-273
T(°C) = 570-273
T(°C) = 297°C
[tex] \tt =>\color{red}297°C [/tex]