construct a triangle with sum of all sides 12 cm and two base angle are 45 and 60 degree each.write the step of construction About the author Mary

Answer: Draw a line segment PQ = AB + BC + CA = 12 cm. Make ∠ LPQ= 45° and ∠ MQP = 60° Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A. Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively. Join AB and AC. Reply

1)Draw a line segment PQ = AB + BC + CA = 12 cm. 2)Make ∠ LPQ= 45° and ∠ MQP = 60° 3)Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A. 4)Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively. 5)Join AB and AC. Reply

Answer:Draw a line segment PQ = AB + BC + CA = 12 cm.

Make ∠ LPQ= 45° and ∠ MQP = 60°

Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.

Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.

Join AB and AC.

1)Draw a line segment PQ = AB + BC + CA = 12 cm.

2)Make ∠ LPQ= 45° and ∠ MQP = 60°

3)Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.

4)Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.

5)Join AB and AC.