CLASS 9TH POLYNOMIALS Question : Factorise the following – 1. 12x³+23x²-4x-15 ( Please give full answer with procedure and Identies. Incorrect / Irrelevant questions will be reported ) About the author Adalynn
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ [tex]\huge\color{cyan}\boxed{\colorbox{black}{Solution:-}}[/tex] Factor the [tex]4 {x}^{2} (3x + 1) – 3x – 1[/tex] first two terms: Notice that we can factor out the negative – from the last two terms: [tex]4 {x}^{2} (3x + 1) – (3x + 1)[/tex] This means we can factor this by grouping. The factoring is already done, so we are left with: [tex](3x -+ 1)( {4x}^{2} – 1)[/tex] You can double-check this by expanding it again using the FOIL method: 12x³+23x²-4x-15 ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ Reply
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[tex]\huge\color{cyan}\boxed{\colorbox{black}{Solution:-}}[/tex]
Factor the
[tex]4 {x}^{2} (3x + 1) – 3x – 1[/tex]
first two terms:
Notice that we can factor out the negative – from the last two terms:
[tex]4 {x}^{2} (3x + 1) – (3x + 1)[/tex]
This means we can factor this by grouping. The factoring is already done, so we are left with:
[tex](3x -+ 1)( {4x}^{2} – 1)[/tex]
You can double-check this by expanding it again using the FOIL method:
12x³+23x²-4x-15
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