check whether the following number are perfect squares is not find the number by which this should be multiplied so that the product is a perfect square also find the square root of the new number obtained 408?
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Answer:
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your answer is
Solution : (i)`402 = 20^2 +2`<br> So, if we subtract `2` from `402`, we get a perfect square and square root of the perfect square will be `20`.<br><br> (ii) `1989 = 44^2+53`<br> So, if we subtract `53` from `1989 `, we get a perfect square and square root of the perfect square will be `44`.<br><br> (iii) `3250 = 57^2+1`<br> So, if we subtract `1` from `3250 `, we get a perfect square and square root of the perfect square will be `57`.<br><br> (iv) `825 = 28^2+41`<br> So, if we subtract `41` from `825 `, we get a perfect square and square root of the perfect square will be `28`.<br><br> (v)`4000 = 63^2+31`<br> So, if we subtract `31` from `4000 `, we get a perfect square and square root of the perfect square will be `63`.<br><br>
Answer:
Hello , dear
your answer is
Solution : (i)`402 = 20^2 +2`<br> So, if we subtract `2` from `402`, we get a perfect square and square root of the perfect square will be `20`.<br><br> (ii) `1989 = 44^2+53`<br> So, if we subtract `53` from `1989 `, we get a perfect square and square root of the perfect square will be `44`.<br><br> (iii) `3250 = 57^2+1`<br> So, if we subtract `1` from `3250 `, we get a perfect square and square root of the perfect square will be `57`.<br><br> (iv) `825 = 28^2+41`<br> So, if we subtract `41` from `825 `, we get a perfect square and square root of the perfect square will be `28`.<br><br> (v)`4000 = 63^2+31`<br> So, if we subtract `31` from `4000 `, we get a perfect square and square root of the perfect square will be `63`.<br><br>
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Answer:
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