calculate the weight of the structure given below assume the suitable dimensions is required length is equal to 8 metre R=50cm r=25cm About the author Eden
Step-by-step explanation: Length of the room = 8m 25cm = 825 cm Breadth of the room = 6m 75cm = 675 cm Height of the room = 4m 50cm = 450 cm Prime factorization of 825, 675 and 450 are as follows: 825 = 3×5×5×11 675 = 3×3×3×5×5 450 = 2×3×3×5×5 Common factors = 3×5×5 H.C.F. = 75 Hence, H.C.F. of 825, 675 and 450 is 75. Therefore the length of the longest tap is 75 cm which can measure the three dimensions of the room exactly. Reply
Step-by-step explanation: Length of the room = 8m 25cm = 825 cm Breadth of the room = 6m 75cm = 675 cm Height of the room = 4m 50cm = 450 cm Prime factorization of 825, 675 and 450 are as follows: 825 = 3×5×5×11 675 = 3×3×3×5×5 450 = 2×3×3×5×5 Common factors = 3×5×5 H.C.F. = 75 Hence, H.C.F. of 825, 675 and 450 is 75. Therefore the length of the longest tap is 75 cm which can measure the three dimensions of the room exactly. please mark me as brainliest Reply
Step-by-step explanation:
Length of the room = 8m 25cm = 825 cm
Breadth of the room = 6m 75cm = 675 cm
Height of the room = 4m 50cm = 450 cm
Prime factorization of 825, 675 and 450 are as follows:
825 = 3×5×5×11
675 = 3×3×3×5×5
450 = 2×3×3×5×5
Common factors = 3×5×5
H.C.F. = 75
Hence, H.C.F. of 825, 675 and 450 is 75.
Therefore the length of the longest tap is 75 cm which can measure the three dimensions of the room exactly.
Step-by-step explanation:
Length of the room = 8m 25cm = 825 cm
Breadth of the room = 6m 75cm = 675 cm
Height of the room = 4m 50cm = 450 cm
Prime factorization of 825, 675 and 450 are as follows:
825 = 3×5×5×11
675 = 3×3×3×5×5
450 = 2×3×3×5×5
Common factors = 3×5×5
H.C.F. = 75
Hence, H.C.F. of 825, 675 and 450 is 75.
Therefore the length of the longest tap is 75 cm which can measure the three dimensions of the room exactly.
please mark me as brainliest