Given : [tex] \tt \: Principal \: : \: 5000[/tex] [tex] \tt \: Rate \: of \: Interest \: : 4 \% [/tex] [tex] \tt \: Time \: : \: 2 \: years.[/tex] To find : [tex] \tt \: We \: have \: to \: find \: the \: simple \: interest. [/tex] [tex] \bf \: So, \: Let’s \: Start \: : [/tex] [tex] \sf \: Formula \: to \: find \: the \: Simple \: Interest \: : [/tex] [tex] \green{\boxed{ \sf \: \red{ SI \: = \: \dfrac{P \times R \times T }{100} }}}[/tex] [tex] \underline{ \sf \: Now \: we \: will \: substitute \: all \: the \: value \: into \: the \: formula.}[/tex] [tex]{ \sf \: { SI \: = \: \dfrac{5000\times 4 \times 2}{100} }}[/tex] [tex]{ \sf \: { SI \: = \: \dfrac{50\times 4 \times 2}{1} }}[/tex] [tex]{ \sf \: { SI \: = \: {50\times 4 \times 2} }} \: = \: \red{400}[/tex] [tex] \boxed{ \purple{\sf \red\star \: \ \underline{ So, \: the \: SI \: = \: Rs. \: 400 } \:\red\star }}[/tex] Reply
Given :
[tex] \tt \: Principal \: : \: 5000[/tex]
[tex] \tt \: Rate \: of \: Interest \: : 4 \% [/tex]
[tex] \tt \: Time \: : \: 2 \: years.[/tex]
To find :
[tex] \tt \: We \: have \: to \: find \: the \: simple \: interest. [/tex]
[tex] \bf \: So, \: Let’s \: Start \: : [/tex]
[tex] \sf \: Formula \: to \: find \: the \: Simple \: Interest \: : [/tex]
[tex] \green{\boxed{ \sf \: \red{ SI \: = \: \dfrac{P \times R \times T }{100} }}}[/tex]
[tex] \underline{ \sf \: Now \: we \: will \: substitute \: all \: the \: value \: into \: the \: formula.}[/tex]
[tex]{ \sf \: { SI \: = \: \dfrac{5000\times 4 \times 2}{100} }}[/tex]
[tex]{ \sf \: { SI \: = \: \dfrac{50\times 4 \times 2}{1} }}[/tex]
[tex]{ \sf \: { SI \: = \: {50\times 4 \times 2} }} \: = \: \red{400}[/tex]
[tex] \boxed{ \purple{\sf \red\star \: \ \underline{ So, \: the \: SI \: = \: Rs. \: 400 } \:\red\star }}[/tex]
Answer:
400/- is the interest
Step-by-step explanation: