Calculate average velocity of a bus moving form rest to 25 m/s gradually over the course
in 5s.​

2 thoughts on “<br />Calculate average velocity of a bus moving form rest to 25 m/s gradually over the course<br />in 5s.​”

1. Answer:

   Equation Symbol breakdown Meaning in words

   v ˉ = Δ x Δ t \bar v = \dfrac{\Delta x} {\Delta t} vˉ=ΔtΔx v ˉ \bar v vˉv, with, \bar, on top is average velocity, Δ x \Delta x Δx is displacement, and Δ t \Delta t Δt is change in time. Average velocity is displacement divided by time interval of the displacement.

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2. Answer:

   62.5m

   Step-by-step explanation:

   It is given that the body goes from 0 m/s to 25 m/s in 5 sec.

   Formulae Used:

   v = u + at

   s = ut + ½(at²)

   v = final velocity of the body

   u = initial velocity of the body

   a = acceleration of the body

   t = time taken

   Step 1 :

   u = 0 m/s

   v = 25 m/s

   t = 5 sec

   a = ?

   It is given that the body goes from 0 m/s to 25 m/s in 5 sec.

   So,

   From v = u + at,

   [tex]25 m/s \: = 0 m/s \: + a(5 sec)[/tex]

   so,

   [tex]a \: = 25 \div 5 \\ [/tex]

   [tex]a \: = 5 \:m/s²[/tex]

   Step 2:

   s = ut + ½(at²)

   s = ?

   u = 0 m/s

   v = 25 m/s

   t = 5 sec

   By substituting in that formula, we get s = 62.5m

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