2 thoughts on “<br />Calculate average velocity of a bus moving form rest to 25 m/s gradually over the course<br />in 5s.”

Answer:

Equation Symbol breakdown Meaning in words

v ˉ = Δ x Δ t \bar v = \dfrac{\Delta x} {\Delta t} vˉ=ΔtΔx v ˉ \bar v vˉv, with, \bar, on top is average velocity, Δ x \Delta x Δx is displacement, and Δ t \Delta t Δt is change in time. Average velocity is displacement divided by time interval of the displacement.

Answer:## Equation Symbol breakdown Meaning in words

## v ˉ = Δ x Δ t \bar v = \dfrac{\Delta x} {\Delta t} vˉ=ΔtΔx v ˉ \bar v vˉv, with, \bar, on top is average velocity, Δ x \Delta x Δx is displacement, and Δ t \Delta t Δt is change in time. Average velocity is displacement divided by time interval of the displacement.

Answer:## 62.5m

Step-by-step explanation:It is given that the body goes from 0 m/s to 25 m/s in 5 sec.

FormulaeUsed:v = u + at

s = ut + ½(at²)

v = final velocity of the body

u = initial velocity of the body

a = acceleration of the body

t = time taken

Step1:u = 0 m/s

v = 25 m/s

t = 5 sec

a = ?

It is given that the body goes from 0 m/s to 25 m/s in 5 sec.

So,

From v = u + at,

[tex]25 m/s \: = 0 m/s \: + a(5 sec)[/tex]

so,

[tex]a \: = 25 \div 5 \\ [/tex]

[tex]a \: = 5 \:m/s²[/tex]

Step2:s = ut + ½(at²)

s = ?

u = 0 m/s

v = 25 m/s

t = 5 sec

By substituting in that formula, we get s = 62.5m