(c) If sin 3A = cos (A-26°), where 3A is an acute angle, find the value of A​

2 thoughts on “<br /><br />(c) If sin 3A = cos (A-26°), where 3A is an acute angle, find the value of A​”

1. Answer:

   A=29o

   Step-by-step explanation:

   Given that

   sin3A=cos(A−26)

   cos(90−3A)=cos(A−26) [sinθ=cos(90−θ)]

   Comparing angles

   90−3A=A−26

   −3A−A=−26−90

   −4A=−116

   A=4116

   A=29o

   I hope you understand..

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2. Answer:

   sin 3A = cos (A-26°)

   cos(90°-3A)=cos (A-26°)

   90°-3A=A-26°

   90°+26°=A+3A

   116°=4A

   A=29°

   Reply