by what number should 5/3^-2 be multiplied so that the product may be 7/3^-1 ? About the author Peyton
Answer: Make me as a Brainlist pls Step-by-step explanation: [tex] \frac{5}{ {3}^{ – 2} } \times x = \frac{7}{ {3}^{ – 1} } \\ = > 5 \times {3}^{2} \times x = 7 \times {3}^{1} \\ = > 5 \times 9 \times x = 21 \\ = > 45x = 21 \\ = > x = \frac{21}{45} = \frac{7}{15} \\ = > x = \frac{7}{15} [/tex] Reply
Answer: Step-by-step explanation: Solution. Hence, (5/3)−2 should be multiplied by 25/21 to obtain (7/3)−1. Mark me brilliant Reply
Answer:
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Step-by-step explanation:
[tex] \frac{5}{ {3}^{ – 2} } \times x = \frac{7}{ {3}^{ – 1} } \\ = > 5 \times {3}^{2} \times x = 7 \times {3}^{1} \\ = > 5 \times 9 \times x = 21 \\ = > 45x = 21 \\ = > x = \frac{21}{45} = \frac{7}{15} \\ = > x = \frac{7}{15} [/tex]
Answer:
Step-by-step explanation:
Solution. Hence, (5/3)−2 should be multiplied by 25/21 to obtain (7/3)−1.
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