area of square formed on diagonal of a rectangle as its side is 108 1/3% more than the area of rectangle .if the perimeter of rect

area of square formed on diagonal of a rectangle as its side is 108 1/3% more than the area of rectangle .if the perimeter of rectangle is 28units . find difference between the side of rectangle​

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  1. Answer:

    l-b=8-6=2

    Step-by-step explanation:

    Let the sides of the rectangle be l and b respectively.

    From the given data,

    (√l2 + b2) = (1 + 108 1/3 %)lb

    => l2 + b2 = (1 + 325/3 * 1/100)lb

    = (1 + 13/12)lb

    = 25/12 lb

    => (l2 + b2)/lb = 25/12

    12(l2 + b2) = 25lb

    Adding 24lb on both sides

    12l2 + 12b2 + 24lb = 49lb

    12(l2 + b2 + 2lb) = 49lb

    but 2(l + b) = 28 => l + b = 14

    12(l + b)2 = 49lb

    => 12(14)2 = 49lb

    => lb = 48

    Since l + b = 14, l = 8 and b = 6

    l – b = 8 – 6 = 2m.

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