Area of right angle triangle is 24cm2 and perimeter is 24cm. Find the lengths of sides of triangle ? About the author Genesis

Answer: Let x cm be the one of the sides, then (x−2)cm be another side. Area of triangle =24cm 2 (given) We know, Area of triangle = 2 1 (Base×height) ⇒24= 2 1 ×x×(x−2) ⇒48=x 2 −2x or x 2 −2x−48=0 Solving above equation, we have (x+6)(x−8)=0 x=−6 or x=8 Since length measure cannot be negative, so neglect x=−6 One side =8cm Another Side =x−2=8−2=6cm Apply Pythagoras theorem: Hypotenuse 2 = Base 2 + Perpendicular 2 Hypotenuse 2 = (8 2 +6 2 ) Hypotenuse = 100 =10 Therefore, perimeter of triangle = Sum of all the sides =(6+8+10)cm=24cm Reply

Answer:Let x cm be the one of the sides, then (x−2)cm be another side.

Area of triangle =24cm

2

(given)

We know, Area of triangle =

2

1

(Base×height)

⇒24=

2

1

×x×(x−2)

⇒48=x

2

−2x

or x

2

−2x−48=0

Solving above equation, we have

(x+6)(x−8)=0

x=−6 or x=8

Since length measure cannot be negative, so neglect x=−6

One side =8cm

Another Side =x−2=8−2=6cm

Apply Pythagoras theorem:

Hypotenuse

2

= Base

2

+ Perpendicular

2

Hypotenuse

2

=

(8

2

+6

2

)

Hypotenuse =

100

=10

Therefore, perimeter of triangle = Sum of all the sides =(6+8+10)cm=24cm