Area of right angle triangle is 24cm2 and perimeter is 24cm. Find the lengths of sides of triangle ? About the author Genesis
Answer: Let x cm be the one of the sides, then (x−2)cm be another side. Area of triangle =24cm 2 (given) We know, Area of triangle = 2 1 (Base×height) ⇒24= 2 1 ×x×(x−2) ⇒48=x 2 −2x or x 2 −2x−48=0 Solving above equation, we have (x+6)(x−8)=0 x=−6 or x=8 Since length measure cannot be negative, so neglect x=−6 One side =8cm Another Side =x−2=8−2=6cm Apply Pythagoras theorem: Hypotenuse 2 = Base 2 + Perpendicular 2 Hypotenuse 2 = (8 2 +6 2 ) Hypotenuse = 100 =10 Therefore, perimeter of triangle = Sum of all the sides =(6+8+10)cm=24cm Reply
Answer:
Let x cm be the one of the sides, then (x−2)cm be another side.
Area of triangle =24cm
2
(given)
We know, Area of triangle =
2
1
(Base×height)
⇒24=
2
1
×x×(x−2)
⇒48=x
2
−2x
or x
2
−2x−48=0
Solving above equation, we have
(x+6)(x−8)=0
x=−6 or x=8
Since length measure cannot be negative, so neglect x=−6
One side =8cm
Another Side =x−2=8−2=6cm
Apply Pythagoras theorem:
Hypotenuse
2
= Base
2
+ Perpendicular
2
Hypotenuse
2
=
(8
2
+6
2
)
Hypotenuse =
100
=10
Therefore, perimeter of triangle = Sum of all the sides =(6+8+10)cm=24cm