apply equaton (x+y)÷2

a) -10,-6
b)-4,2
c)8,-20​

1 thought on “apply equaton (x+y)÷2<br /><br /> a) -10,-6<br /> b)-4,2<br /> c)8,-20​”

1. Answer:

   Hope this answer helps you ??

   Step-by-step explanation:

   The straight line in the first case passes through (4,0) and (0,4).

   Hence its equation (by application of intercept form) will be x+y=4…(i)

   The straight line in the second case passes through (0,−6) and (−8,−8).

   Hence, its equation is given by

   x+8

   y+8

   ​

   =

   x

   y+6

   ​

   ⇒8x=6x+8y+48

   ⇒2x=8y+48

   ⇒x−4y=24….(ii)

   Solving equation (i) and (ii) gives us the intersection point as x=8 and y=−4.

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