Angle sum of a polygon whose number of sides are 12 is _____​

2 thoughts on “Angle sum of a polygon whose number of sides are 12 is _____​”

1. Answer:

   formula is N-2 × 180

   Step-by-step explanation:

   N= 12

   subtract by 2

   with that multiply by 108

   answer = 1800

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2. We know,

   Angle sum of a n-sided polygon

   [tex] = 180 \degree (n – 2)[/tex]

   As, the number of sides are 12

   We get,

   [tex] \implies180 \degree (12 – 2)[/tex]

   [tex] = 180 \degree (10) = 1800 \degree[/tex]

   Reply