Angle sum of a polygon whose number of sides are 12 is _____

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Angle sum of a polygon whose number of sides are 12 is _____

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Answer:formula is N-2 × 180

Step-by-step explanation:N= 12

subtract by 2

with that multiply by 108

answer = 1800

We know,

Angle sum of a n-sided polygon

[tex] = 180 \degree (n – 2)[/tex]

As, the number of sides are 12

We get,

[tex] \implies180 \degree (12 – 2)[/tex]

[tex] = 180 \degree (10) = 1800 \degree[/tex]