an oxide of Nitrogen has a molecular weight of 46 total number of electrons in one molecule of the compound is About the author Cora
now let us assume that in that oxide *per molecule* there are ‘x’ atoms of nitrogen and ‘y’ atoms of oxygen then molecular weigh is given by : X×14 + Y×16 [ since atomic weigh of nitrogen is 14 and that of oxygen is 16] now according to question molecualr weigh is 46 => 14x +16y = 46 according to hit and trial method, X =1 and Y=2 => chemical formulae of compound was NO2 => total number of electrons in that compound is : 7(from nitrogen) + 2×8(from two atom of oxygen) =7 + 16 =23. HOPE IT HELPS YOU MUCH Reply
now let us assume that in that oxide *per molecule* there are ‘x’ atoms of nitrogen and ‘y’ atoms of oxygen then molecular weigh is given by :
X×14 + Y×16 [ since atomic weigh of nitrogen is 14 and that of oxygen is 16]
now according to question molecualr weigh is 46 =>
14x +16y = 46
according to hit and trial method,
X =1 and Y=2
=> chemical formulae of compound was NO2
=> total number of electrons in that compound is :
7(from nitrogen) + 2×8(from two atom of oxygen)
=7 + 16
=23.
HOPE IT HELPS YOU MUCH