an object of size 4cm is placed at a distance of 15 cm Infront of a concave mirror of focal length 10 cm. find the size position a

2 thoughts on “an object of size 4cm is placed at a distance of 15 cm Infront of a concave mirror of focal length 10 cm. find the size position a”

1. Solution

   Given :–

   • Focal length of concave mirror = 10 cm
   • Size of object = 4 cm
   • Distance of object from focal length = 15 cm

   Find :–

   • Image position and its nature

   Explanation

   Using mirror Formula

   [tex]\boxed{\tt{\red{\:\dfrac{1}{f}\:=\:\dfrac{1}{v}+\dfrac{1}{u}}}}[/tex]

   Where,

   • f = – 10 cm
   • h = – 15 cm

   Keep all values in formula

   ==> 1/(-10) = 1/(-15) + 1/v

   ==> 1/v = -1/10 + 1/15

   ==> 1/v = (-15 + 10)/150

   ==> 1/v = (-5)/150

   ==> 1/v = -1/30

   Or,

   ==> v = – 30 cm.

   Distance of image is (-ve) sign , that’s means image be real .

   _____________________

   Reply

2. [tex]\huge\boxed{\fcolorbox{white}{gray}{Answer:⇢}}[/tex]

   Given :-

   • Focal length of concave mirror = 10 cm

   • Size of object = 4 cm

   • Distance of object from focal length = 15 cm

   To Find :-

   • Image position and its nature.

   Explanation :-

   Using Mirror Formula :-

   [tex]\boxed{\tt{\pink{\:\dfrac{1}{f}\:=\:\dfrac{1}{v}+\dfrac{1}{u}}}}[/tex]

   Where,

   • f = – 10 cm
   • h = – 15 cm

   Keep all values in formula

   • ➟ 1/(-10) = 1/(-15) + 1/v

   • ➟ 1/v = -1/10 + 1/15

   • ➟ 1/v = (-15 + 10)/150

   • ➟ 1/v = (-5)/150

   • ➟ 1/v = -1/30

   Or,

   • ➟ v = – 30 cm.

   • Distance of image is (-ve) sign , that’s means image be real .

   ________________________

   Reply