An electric pole is 10 m high. A stell wire tied to the top of the pole is affixed at a point on the ground to keep the upright. I

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1. [tex]\huge\bf{Solution}[/tex]

   Given :

   OA = 10 m ( electric pole)

   ∠B = 45°

   Let OA be the electric Pole and B be the point on the ground.

   Let BA = x cm

   In ∆ABO

   sin 45° = AO /AB (perpendicular/ hypotenuse)

   1 / √ 2 = 10 / x

   x = 10 √2

   x = 10 × 1.414 (Given √2 = 1.414)

   x = 14.14 m

   Hence, length of the wire is 14.14 m.

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