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ABCD is a quadrilateral with Ag = 20 cm, BC-15 cm,
CD = 25 cm 4 = 30 cm and ABC = 90″ The area of
the quadrilateral ABCD

By Amaya

ABCD is a quadrilateral with Ag = 20 cm, BC-15 cm,
CD = 25 cm 4 = 30 cm and ABC = 90″ The area of
the quadrilateral ABCD​

About the author
Amaya

Match the following:-
A
B
(1)
1
1
and
(a) Reciprocal inverse
7 7
(2) (-1) + 1 = 0 (b)

when 0 is multiplied by any negative integers their product will be a positive number ,a whole number , an integer , none of thes

2 thoughts on “ABCD is a quadrilateral with Ag = 20 cm, BC-15 cm,<br />CD = 25 cm 4 = 30 cm and ABC = 90″ The area of<br />the quadrilateral ABCD”

  1. Answer:

    What is the area of a quadrilateral ABCD in which AB = 10 cm, BC = 25 cm, CD = 8 cm, DA = 15 cm and ∠ADC = 90 degree?

    ABCD is a quadrilateral and angle ADC is 90°. Draw a quadrilateral ABCD and join A to C.

    In ∆ADC, Pythagoras can be used

    AC2=AD2+DC2

    AC2=152+82

    AC=17cm

    Area of ΔADC=1/2×base×height

    Area of ADC=1/2×15×8

    Area of ADC=60 sq cm

    Now area of ΔABC

    S=10+25+17/2

    S=26cm

    Area of ΔABC=√26(26–10)(26–25)(26–17)

    Area of ΔABC=√26×16×1×9

    Area of ΔABC=12√26cm2

    Area of ABCD=(60+12√26) sq cm

    Reply

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