ABCD is a parallelogram. E and Fare the mid-points of the sides
AB and CD respectively. Prove that the line segments A

ABCD is a parallelogram. E and Fare the mid-points of the sides
AB and CD respectively. Prove that the line segments AF and CE trisect (divide into three
equal parts) the diagonal BD.

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  1. Step-by-step explanation:

    Given = ABCD is a parallelogram where E&F are mid point of side Ab and CD respectively.

    To prove = Af&EC trisect BD

    prove= AB|| CD {opposite side of a parallelogram

    AE||CF {parts of parallels line}

    AB=CD {opposite sides of a parallelogram}

    ½AB ½ CD

    AE=CF {f is the mid point of CD}

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