– ABCD in which AB = 4.2 cm, BC = 4.5 cm, CD = 4 cm, DA = 4.8 cm, and angle A = 72º construct a quadrilateral . About the author Parker
Answer: Given : ABCD in which AB=4.2cm, BC=4.5cm, CD=4 cm, DA=4.8 cm and angle A =72° To Find : construct Triangle Solution: Step 1 : Draw a line segment AB = 4.2 cm Step 2 : Draw a ray at an angle of 72° at A on BA using protractor. Step 3 : Using compass width = 4.8 cm and taking A as center cut the ray drawn in previous step at D Step 4 : Using Compass width = 4.5 cm and taking B as center draw an arc Step 5 : Using Compass width = 4 cm and taking D as center draw an arc intersecting arc drawn in previous step at C Step 6 : Join BC & CD. Quadrilateral ABCD is constructed. Learn More: Construct quadrilateral PQRS such that PQ=PS=PR= 9cm ,QR . Reply
Answer:
Given : ABCD in which AB=4.2cm, BC=4.5cm, CD=4 cm, DA=4.8 cm and angle A =72°
To Find : construct Triangle
Solution:
Step 1 : Draw a line segment AB = 4.2 cm
Step 2 : Draw a ray at an angle of 72° at A on BA using protractor.
Step 3 : Using compass width = 4.8 cm and taking A as center cut the ray drawn in previous step at D
Step 4 : Using Compass width = 4.5 cm and taking B as center draw an arc
Step 5 : Using Compass width = 4 cm and taking D as center draw an arc intersecting arc drawn in previous step at C
Step 6 : Join BC & CD.
Quadrilateral ABCD is constructed.
Learn More:
Construct quadrilateral PQRS such that PQ=PS=PR= 9cm ,QR .