ABC is an isosceles triangle with AB = AC. If its perimeter is 36 cm and BC = 16 cm, find(4)its area. About the author Luna
Answer: For triangle ABC, perimeter = AB+BC+CA & AB=AC ∴AB=AC= 1\2(36−16)cm=10cm Now, triangle ABE be a right angle triangle. Then by pythagoras theorem, we have h ^ +8 ^ =10 ^ ⇒h=6cm Area of ΔABC =1\2×16cm×6cm=48cm^ Reply
Sides are AB=AC=10 cm and BC=16cm Half perimeter =(a+b+c)/2 = 36/2 =18cm Area =root((s)(s-a)(s-b)(s-c)) = root(18*2*8*8) = 6*8 = 48 Therefore area of triangle is 48 cm^2 Please mark as brainliest Reply
Answer:
For triangle ABC, perimeter = AB+BC+CA & AB=AC
∴AB=AC= 1\2(36−16)cm=10cm
Now, triangle ABE be a right angle triangle.
Then by pythagoras theorem, we have
h ^ +8 ^ =10 ^
⇒h=6cm
Area of ΔABC =1\2×16cm×6cm=48cm^
Sides are AB=AC=10 cm and BC=16cm
Half perimeter =(a+b+c)/2 = 36/2 =18cm
Area =root((s)(s-a)(s-b)(s-c)) = root(18*2*8*8) = 6*8 = 48
Therefore area of triangle is 48 cm^2
Please mark as brainliest