ABC + BC.57. In AABC, if ZB = 90°, then find the missing quantities in the following table whichare marked by question sign (?):Sr. No.ABBCAC(1)12 cm(?)37 cmnsh(2)21 cm20 cm(?)(3)39 cm89 cm(?)55 cmod(4)(?)73 cm About the author Isabella
Given :- ABC, if ∠B = 90°, then find the missing quantities in the following table :- AB BC AC (1) 12 ? 37 (2) 21 20 ? (3) 39 ? 89 (4) ? 55 73 Solution :- we know that, Angle opposite to right angle = Hypotenuse = AC AB² + BC² = AC² (Pythagoras theorem) . so, → AB² + BC² = AC² → 12² + BC² = 37² → BC² = 37² – 12² → BC² = (37 + 12)(37 – 12) → BC² = 49 * 25 → BC² = 7² * 5² → BC² = (7 * 5)² → BC = 35 (Ans.1) similarly, → AB² + BC² = AC² → 21² + 20² = AC² → AC² = 441 + 400 → AC² = 841 → AC = √(841) → AC = 29 (Ans.2) and, → AB² + BC² = AC² → 39² + BC² = 89² → BC² = 89² – 39² → BC² = (89 + 39)(89 – 39) → BC² = 128 * 50 → BC² = 6400 → BC = √(6400) → BC = 80 (Ans.3) also, → AB² + BC² = AC² → AB² + 55² = 73² → AB² = 73² – 55² → AB² = (73 + 55)(73 – 55) → AB² = 128 * 18 → AB² = 2304 → AB² = √(2304) → AB = 48 (Ans.4) Learn more :- triangle PQR measure PQR =90 degree and the length of the hypotenuse PR is 13cm find PQ square + QR square. with solutio… https://brainly.in/question/36476505 Q.3 Find x so that the triangle shown below is a right triangle 16x (2 MARKS https://brainly.in/question/36234424 *काटकोन त्रिकोणात काटकोन करणाऱ्या बाजू a सेमी व b सेमी यांप्रमाणे आहेत ,तर सर्वांत मोठ्या बाजूची लांबी किती असेल?* 1️⃣ … https://brainly.in/question/37046697 Reply
Step-by-step explanation: ABC + BC. 57. In AABC, if ZB = 90°, then find the missing quantities in the following table which are marked by question sign (?): Sr. No. AB BC AC (1) 12 cm (?) 37 cm nsh (2) 21 cm 20 cm (?) (3) 39 cm 89 cm (?) 55 cm od (4) (?) 73 cm Reply
Given :- ABC, if ∠B = 90°, then find the missing quantities in the following table :-
AB BC AC
(1) 12 ? 37
(2) 21 20 ?
(3) 39 ? 89
(4) ? 55 73
Solution :-
we know that,
so,
→ AB² + BC² = AC²
→ 12² + BC² = 37²
→ BC² = 37² – 12²
→ BC² = (37 + 12)(37 – 12)
→ BC² = 49 * 25
→ BC² = 7² * 5²
→ BC² = (7 * 5)²
→ BC = 35 (Ans.1)
similarly,
→ AB² + BC² = AC²
→ 21² + 20² = AC²
→ AC² = 441 + 400
→ AC² = 841
→ AC = √(841)
→ AC = 29 (Ans.2)
and,
→ AB² + BC² = AC²
→ 39² + BC² = 89²
→ BC² = 89² – 39²
→ BC² = (89 + 39)(89 – 39)
→ BC² = 128 * 50
→ BC² = 6400
→ BC = √(6400)
→ BC = 80 (Ans.3)
also,
→ AB² + BC² = AC²
→ AB² + 55² = 73²
→ AB² = 73² – 55²
→ AB² = (73 + 55)(73 – 55)
→ AB² = 128 * 18
→ AB² = 2304
→ AB² = √(2304)
→ AB = 48 (Ans.4)
Learn more :-
triangle PQR measure PQR =90 degree and the length of the hypotenuse PR is 13cm find PQ square + QR square. with solutio…
https://brainly.in/question/36476505
Q.3 Find x so that the triangle shown below is a right triangle
16x
(2 MARKS
https://brainly.in/question/36234424
*काटकोन त्रिकोणात काटकोन करणाऱ्या बाजू a सेमी व b सेमी यांप्रमाणे आहेत ,तर सर्वांत मोठ्या बाजूची लांबी किती असेल?*
1️⃣ …
https://brainly.in/question/37046697
Step-by-step explanation:
ABC + BC.
57. In AABC, if ZB = 90°, then find the missing quantities in the following table which
are marked by question sign (?):
Sr. No.
AB
BC
AC
(1)
12 cm
(?)
37 cm
nsh
(2)
21 cm
20 cm
(?)
(3)
39 cm
89 cm
(?)
55 cm
od
(4)
(?)
73 cm