A turtle can walk \dfrac{1}{12}
12
1

start fraction, 1, divided by, 12, end fraction of a kilometer i

By Ruby

A turtle can walk \dfrac{1}{12}
12
1

start fraction, 1, divided by, 12, end fraction of a kilometer in an hour. The turtle is \dfrac15
5
1

start fraction, 1, divided by, 5, end fraction of a kilometer away from a pond.
At this speed, how long will it take the turtle to reach the pond?

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Ruby

2 thoughts on “A turtle can walk \dfrac{1}{12} <br /> 12<br /> 1<br /> ​ <br /> start fraction, 1, divided by, 12, end fraction of a kilometer i”

  1. Answer:

    Given :

    Distance covered by turtle = 1/5 km

    Speed of turtle = 1/12 km/h

    To Find :

    Time taken

    Solution :

    As we know that

    [tex]{\boxed{\pink{\underline{\frak {Time = \dfrac{Distance}{Speed}}}}}}[/tex]

    Time = (1/5)/(1/12)

    Time = 1/5 ÷ 1/12

    Time = 1/5 × 12/1

    Time = 12/5 hrs

    Therefore,

    • Time taken is 12/5 hrs.
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  2. Given

    • [tex]s=\dfrac{1}{12}[/tex] kilometer/hour

    Let the speed be [tex]s[/tex].

    • [tex]d=\dfrac{1}{5}[/tex] kilometer

    Let the distance be [tex]d[/tex].

    • [tex]t=[/tex]? hour

    Let the time be [tex]t[/tex].

    Solution

    The speed is the ratio of distance and time, so [tex]\mathrm{speed=\dfrac{distance}{time} }[/tex].

    [tex]\Longleftrightarrow \dfrac{1}{12}= \dfrac{\dfrac{1}{5} }{t}[/tex]

    [tex]\Longleftrightarrow \dfrac{1}{12} =\dfrac{1}{5t}[/tex]

    [tex]\Longleftrightarrow 5t=12[/tex] [tex]\therefore t=\dfrac{12}{5}[/tex]

    The turtle spends [tex]\dfrac{12}{5}[/tex] hour, or [tex]2[/tex] hours [tex]24[/tex] minutes to reach the pond.

    Learn More

    • What is a compound fraction?

    A fraction, which has fractions in either the numerator and denominator.

    • How is the calculation of a compound fraction done?

    [tex]\dfrac{\dfrac{a}{b} }{\dfrac{c}{d} } =\dfrac{a}{b} \div \dfrac{c}{d}[/tex]

    [tex]=\dfrac{a}{b} \times \dfrac{d}{c}[/tex]

    [tex]=\dfrac{ad}{bc}[/tex]

    Changing as division, then use multiplication of the inverse. Done!

    Reply

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