# A toy is in the combined form of a cylinder and a cone having the equal basewhose diameter is 10 cm. The length of the cylin

A toy is in the combined form of a cylinder and a cone having the equal base
whose diameter is 10 cm. The length of the cylindrical part is 14 cm and
height of the cone is 12 cm of that toy. If the measurement of diameter and
height of the cone are interchanged and formed the next similar toy, find
which toy costs more for the painting at the same rate for per square
centimeter.​

### 1 thought on “A toy is in the combined form of a cylinder and a cone having the equal base<br />whose diameter is 10 cm. The length of the cylin”

1. Height of cylinder =40cm=h

Height of cone =40cm=h

Total surface area of toy = surface area of hemisphere + surface are of cylinder + surface area of cone.

=2πr

2

+2πrh+πrl

l

2

=r

2

+h

2

=3

2

+4

2

=9+16=25

l

2

=25⇒l=

25

=5cm

Curved surface area of hemisphere =2πr

2

=2×

7

22

×3

2

=56.57cm

2

Curved surface area of cylinder =2πrh

=2(

7

22

)×3×40

=754.28cm

2

Curved surface area of cone =πrl

=

7

22

×3×5

=47.14cm

2

∴ Total surface area of toy =56.57cm

2

+754.28cm

2

+47.14cm

2

=(56.57+47.14+754.28)cm

2

=857.99cm

2

.